Primary exercises
- Manually created factor.
In a study participants were asked whether their sport activity is
none, oncePerWeek, severalPerWeek
or daily.
Build a proper factor for the responses below and store it in a variable
w.
Print the factor.
Write the code to count the numbers of occurrences of each level and
print the counts.
severalPerWeek, none, none, oncePerWeek, oncePerWeek, oncePerWeek, oncePerWeek, ?, none, none
v <- c( "severalPerWeek", "none", "none", "oncePerWeek", "oncePerWeek", "oncePerWeek", "oncePerWeek", NA, "none", "none" )
w <- factor( v, levels = c( "none", "oncePerWeek", "severalPerWeek", "daily" ) )
w
[1] severalPerWeek none none oncePerWeek oncePerWeek oncePerWeek oncePerWeek <NA> none
[10] none
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 5 × 2
f n
<fct> <int>
1 none 4
2 oncePerWeek 4
3 severalPerWeek 1
4 daily 0
5 <NA> 1
- A factor with a random content.
Read help about the function sample.
Then study and try the following lines of code to understand the
results.
Next, understand why an error is generated and use replace
argument to generate a vector with 100 samples.
Store this vector in a variable v and build a factor
w from it.
Finally, count the numbers of occurrences of each level in
w.
Ensure, that levels are in order provided in the variable
lvs.
lvs <- c( "none", "oncePerWeek", "severalPerWeek", "daily" )
sample( lvs, 3 )
[1] "daily" "oncePerWeek" "none"
sample( lvs, 3 )
[1] "none" "severalPerWeek" "oncePerWeek"
sample( lvs, 3 )
[1] "daily" "oncePerWeek" "none"
sample( lvs, 100 )
Error in sample.int(length(x), size, replace, prob): cannot take a sample larger than the population when 'replace = FALSE'
v <- sample( lvs, 100, replace = TRUE )
w <- factor( v, levels = lvs )
w
[1] oncePerWeek severalPerWeek daily oncePerWeek oncePerWeek none oncePerWeek severalPerWeek daily
[10] severalPerWeek none daily oncePerWeek oncePerWeek daily severalPerWeek daily severalPerWeek
[19] daily none daily severalPerWeek severalPerWeek daily severalPerWeek daily severalPerWeek
[28] oncePerWeek severalPerWeek oncePerWeek daily daily oncePerWeek severalPerWeek severalPerWeek oncePerWeek
[37] oncePerWeek none daily severalPerWeek severalPerWeek none none none none
[46] daily daily oncePerWeek daily severalPerWeek oncePerWeek severalPerWeek oncePerWeek severalPerWeek
[55] none severalPerWeek oncePerWeek none severalPerWeek severalPerWeek oncePerWeek oncePerWeek daily
[64] daily none daily oncePerWeek daily none severalPerWeek oncePerWeek severalPerWeek
[73] oncePerWeek none none daily severalPerWeek daily oncePerWeek none severalPerWeek
[82] severalPerWeek daily daily oncePerWeek oncePerWeek severalPerWeek oncePerWeek none none
[91] none severalPerWeek severalPerWeek none severalPerWeek severalPerWeek oncePerWeek none severalPerWeek
[100] oncePerWeek
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 4 × 2
f n
<fct> <int>
1 none 20
2 oncePerWeek 26
3 severalPerWeek 31
4 daily 23
- Reordering factor levels.
When a factor is shown on an axis of a plot, the order is given by its
levels.
The factor w from the previous exercise will be then shown
in this order: none, oncePerWeek,
severalPerWeek, daily.
But for a picture in a manuscript the following order might be needed:
daily, severalPerWeek,
oncePerWeek, none.
Apply to w one of the fct_ functions from the
tidyverse library to produce a factor w2 with
the requested order.
Show the levels of w2.
Again show the number of elements of each level in w2 and
compare it with the table of the previous exercise.
w2 <- fct_relevel( w, c( "daily", "severalPerWeek", "oncePerWeek", "none" ) )
levels( w2 )
[1] "daily" "severalPerWeek" "oncePerWeek" "none"
fct_count( w2 )
# A tibble: 4 × 2
f n
<fct> <int>
1 daily 23
2 severalPerWeek 31
3 oncePerWeek 26
4 none 20